Python: put all function arguments into **kwargs automatically

Description

Say I have the following function, which makes a call to another function:

def f1(arg1, arg2, arg3):
    f2(...)

The arguments of f1 and f2 are the same, or f2 might look like this:

def f2(**kwargs)
    pass  # whatever

The client code is going to call f1 only, and it is required that the signature of f1 explicitly defines all arguments, and thus no **kwargs is allowed for f1.

So, to make a call to f2 from inside f1 I have to do this:

def f1(arg1, arg2, arg3):
    f2(arg1, arg2, arg3)

Question

Is there a way I can pass arguments to f2 without explicitly writing them? Ideally, I think it should look like this:

def f1(arg1, arg2, arg3):
        kwargs = <Some Magic Here>
        f2(**kwargs)

Any magic?