In go, why are both the reflected value and its interface the same when printed?

Excerpt from the Laws of Reflection:

(Why not fmt.Println(v)? Because v is a reflect.Value; we want the concrete value it holds.)

This confuses me because the following code:

var x float64 = 3.4
var v = reflect.ValueOf(x)

fmt.Println("value of x is:", v)
y := v.Interface().(float64) // y will have type float64.
fmt.Println("interface of value of x is:", y)

Prints the same output:

value of x is: 3.4

interface of value of x is: 3.4

Is it because fmt internally finds the concrete value for the reflected v?