How to get interface extending another one (aka super) by its super

Here is my code using Guava:

public interface NetSession {
    void connect();
}

public interface HttpSession extends NetSession {
    void useRestApi();
}

class HttpSessionImpl implements HttpSession {
}

class Test {
    NetSession makeProxy(NetSession session) {
        TypeToken<? extends NetSession> sessionTT = TypeToken.of(session.getClass());
        TypeToken<? extends NetSession>.TypeSet ifaces = sessionTT.getTypes().interfaces();
        //  here we looking for real <? extends NetSession> interface
        Class<? extends NetSession> sessionIface = (Class<? extends NetSession>) ifaces.stream()
                .filter(i -> i.isSubtypeOf(NetSession.class))
                .map(i -> i.getRawType())
                .findAny().orElse(null);
        assert sessionIface != null;
        
        session.connect();
        if (sessionIface == NetSession.class) {
            return session; // as is
        }
        // make extra
        HttpSession httpSession = (HttpSession) session;
        httpSession.useRestApi();
    }
}

My question is: is there more elegant way to find Class of interface by its super? i mean something like:

Class<? extends NetSession> sessionIface = sessionTT.getInterfaceExtending(NetSession.class);
assert sessionIface == HttpSession.class; // is ok in case above

With Guava or else make no difference.