I'm using Scala 2.10.4.
Please bare with the analogy - the actual code is deeply embedded in a complicated program, so rather than explain that, I’ll abstract the problem in a time honoured way to talk about Animals ;-)
In scala I have 2 traits - for example:
Animal, and HouseBase.
I have no access to change Animal, but I inherit from it with classes like Dog, Rabbit, Fish. Annoyingly I can’t change every subclass as I don’t own all the subclasses I use.
My animals all live somewhere - their homes must inherit from HouseBase. I can change HouseBase and it’s subclasses (via another layer of abstraction, if I must).
So a Dog is a subclass of Animal, and would live in a Kennel which is a subclass of HouseBase.
A Rabbit would live in a Hutch, and a Fish in a Tank.
Note there is not a 1:1 relationship enforced here - a Fish could also live in a Pond, and we’d have to be able to handle that too.
What I’d hoped was that -- given a concrete animal (eg Fish), that is referenced via an abstract type Animal, and given a concrete return type (eg Tank), Scala would be able to automagically pick the correct implicit parameter in the design I have below.
object AnimalSelectionProblem extends App {
def abstractFish : Animal = new Fish(true, 20.0)
def concreteFish : Fish = new Fish(false, 30.0)
def abstractDog : Animal = new Dog("tasty bone")
def concreteDog : Dog = new Dog("yummy bone")
def abstractRabbit : Animal = new Rabbit(5)
def concreteRabbit : Rabbit = new Rabbit(10)
import HouseImplicits._
val myTank1: Tank = HouseImplicits.create(abstractFish)
val myTank2: Tank = HouseImplicits.create(concreteFish)
val myKennel1: Kennel = HouseImplicits.create(abstractDog)
val myKennel2: Kennel = HouseImplicits.create(concreteDog) // This works
val myhutch1: Hutch = HouseImplicits.create(abstractDog)
val myhutch2: Hutch = HouseImplicits.create(concreteDog)
}
However there are 2 related problems.
Problem 1 - If the animal is referenced as an abstract, then the implicit parameter will only look for functions that take the abstract type (Animal) rather than the underlying concrete type. I suspect the solution may be to use ClassTags, because Scala doesn’t seem to use runtime time information? I had a go at implementing this and got hopelessly l lost (I’m fairly new to Scala!).
Problem 2 - If my animal can live in more than one type of House then a similar issue occurs, that even if a concrete return type is specified, the compiler will find the 2 implicit objects for Fish ambiguous. I’m a bit stumped about what to do here!
I can dream up solutions with manual boilerplate to match the type at runtime, but this isn’t very extensible.
Any ideas gratefully received! Rest of the code is below.
Thanks,
Phil.
Animals:
trait Animal {
}
class Dog(val boneName: String) extends Animal
class Rabbit(val length: Int) extends Animal
class Fish(val likesFrogs: Boolean, val optimumTemp: Double) extends Animal
Houses and Implicits:
sealed trait HouseBase
// Made up some arbitrary member variables
case class Kennel(posessions: Seq[String]) extends HouseBase
case class Hutch(length: Int) extends HouseBase
case class Tank(waterTemp: Double) extends HouseBase
case class Pond(containsFrog: Boolean) extends HouseBase
sealed trait HouseCreator[A <: Animal, HB <: HouseBase] {
def create(animal: A): HB
}
object HouseImplicits {
implicit object BuildKennelForDog extends HouseCreator[Dog, Kennel] {
override def create(dog: Dog): Kennel = {
new Kennel(Seq(dog.boneName))
}
}
implicit object BuildTankForFish extends HouseCreator[Fish, Tank] {
override def create(fish: Fish): Tank = {
new Tank(fish.optimumTemp)
}
}
implicit object BuildPondForFish extends HouseCreator[Fish, Pond] {
override def create(fish: Fish): Pond = {
new Pond(fish.likesFrogs)
}
}
implicit object BuildHutchForRabbit extends HouseCreator[Rabbit, Hutch] {
override def create(rabbit: Rabbit): Hutch = {
new Hutch(rabbit.length*5)
}
}
def create[A <: Animal, H <: HouseBase](animal: A)(implicit house: HouseCreator[A,H]) : H = {
val newHouse = house.create(animal)
newHouse
}
}
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