Getting two constructor when already have no-argument constructor

public class Base {

    private Base instance;

    private Base() {
    }

    public static class BaseHelper {
        Base instance = new Base();
    }
}

In above example I have one no-argument constructor in base class. Now I'm listing the constructors of this class like this:

Constructor<?>[] constructors = Base.class.getDeclaredConstructors();
System.out.println(constructors);

When running this code I get the following output:

[private com.Base(), com.Base(com.Base)]

This tells me that there are two constructors:

• a private constructor that I have declared


• a public default constructor

Why is this?