How to get the original type (instead of E) for a Parameterized type with generics using reflection? [duplicate]

This question already has an answer here:

• Java generics - obtaining actual type of generic parameter 3 answers

I have a question about Java reflection and generic types.

If I do these instructions:

private static void test() {
    List<String> list = new ArrayList<String>();
    inspect(list.getClass());
}

private static void inspect(Class<?> clazz){
    System.out.println(clazz.getGenericSuperclass());

    Type genericSuperclass = clazz.getGenericSuperclass();
    ParameterizedType pt = (ParameterizedType)genericSuperclass;
    Type rawType = pt.getRawType();
    Type type = pt.getActualTypeArguments()[0];
    System.out.println(rawType + " "+type);

    List<TypeVariable> tps = new ArrayList<TypeVariable>(Arrays.asList(clazz.getTypeParameters()));
    tps.forEach(tp -> {
        Type[] bounds = tp.getBounds();     
        System.out.println(bounds[0] + " " + tp.getTypeName());
    });

}

the output is:

java.util.AbstractList<E>
class java.util.AbstractList E
class java.lang.Object E

I'd like to know if there is a way to obtain the original String.class type instead of a generic E element.

It is possible?

Thanks.