I want to know whether a concrete type implements a specefic interface and print it out. I have written an example [0] with a self defined struct (MyPoint) beeing not an interface-type. MyPoint has the function Read as defined in the interface of io.Reader:
type MyPoint struct {
X, Y int
}
func (pnt *MyPoint) Read(p []byte) (n int, err error) {
return 42, nil
}
The aim is to get the information that the concrete type p implements the interface io.Writer. Therefore I have written a short main trieng to get a true for the check.
func main() {
p := MyPoint{1, 2}
}
The first idea was to check it with the help of reflection and a type-switch and adding check(p)
to to the main-function.
func checkType(tst interface{}) {
switch tst.(type) {
case nil:
fmt.Printf("nil")
case *io.Reader:
fmt.Printf("p is of type io.Reader\n")
case MyPoint:
fmt.Printf("p is of type MyPoint\n")
default:
fmt.Println("p is unknown.")
}
}
The output is: p is of type MyPoint
. After a bit of research I know that I should have expected that because Go's types are static and therefore the type of p is MyPoint and not io.Reader. In addition to that io.Reader is an interface-type which is different to type MyPoint.
I found one solution e.g. at [1] which checks whether MyPoint can be an io.Reader at compile time. It works.
var _ io.Reader = (*MyPoint)(nil)
But that isn't the solution I wanted. Tries like below fails, too. I think it's because of the reason above, isn't it?
i := interface{}(new(MyPoint))
if _, ok := i.(io.Reader); ok {
fmt.Println("i is an io.Reader")
}
pType := reflect.TypeOf(p)
if _, ok := pType.(io.Reader); ok {
fmt.Println("The type of p is compatible to io.Reader")
}
writerType := reflect.TypeOf((*io.Writer)(nil)).Elem()
fmt.Printf("p impl. Writer %t \n", pType.Implements(writerType))
Exists one solution to check whether p implements the interface without compiling? I hope that someone can help me.
[1] Explanation of checking if value implements interface. Golang
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